The Milkman's Puzzle - answer

I haven't really thought this out fully, so there may be a better answer (I might have done a logical circle) or one in fewer steps.

The assumption is that we will, every time, pour milk until the RECEIVING vessel is full or until the pouring vessel is empty. There are no half-pours or "holding the pitcher at an angle so as to get half a can." Label the containers 4, 5, A and B.

4 5   A  B 
A -> 4    4 0   6 10
4 -> 5    0 4   6 10
A -> 4    4 5   2  9
4 -> B    3 5   2 10

5 -> A    3 0   7 10
4 -> 5    0 3   7 10
B -> 4    4 3   7  6
4 -> 5    2 5   7  6 
5 -> A    2 2  10  6

Back to the puzzle.